In this article, we would discuss how to **find the square root a number in Python**. First, it would be through a program. In the latter part of the article, we would do it using **math** module. But, there’s a catch. We can’t find it (sqrt) for a negative number using math module in Python or through our program.

If you want to see how to **find the square root of a negative number**, then follow the article here.

**Note:** Python v3.9 was used to get the desired outcome below.

##### Square root of a number in Python through a program

This is the summary of what we are going to execute next –

- Get a float input from the user,
- Multiply the float input with 0.5,
- Store the result of step 2 in a variable (or, the outcome),
- Print the outcome.

Here is the Python program –

#Program to calculate the square root a number x = float(input('Enter a number: ')) o = x ** 0.5 print("The square root the number ",x," is: ", o)

Lets say the user enters a number: **9**

Output –

The square root the number 9.0 is: 3.0

##### Square root of a number in Python using math module

Alternately, we can get the desired outcome using **math** module. Therefore, first import the **math** module. This way we get to use the **sqrt()** function available through math module.

So,

import math x = float(input('Enter a number: ')) o = math.sqrt(x) print("The square root the number ",x," is: ", o)

The user input: **9**

Output –

The square root the number 9.0 is: 3.0

Pretty similar to we what we did before. Now, consider a scenario where the user enters a negative input: -9

It would throw an error –

ValueError: math domain error

To make sure it doesn’t happen, we may warn user for a negative input beforehand or use if statement;

import math x = float(input('Enter a number: ')) if (x>0): o = math.sqrt(x) print("The square root the number ",x," is: ", o) else: print("Warning: It should be a non-negative input")

**In conclusion**, we have discussed how to find the square root of a non-negative input in Python.